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Originally Posted by
sambb
I think its the intercooler causing pressure drop. To my mind if you have a K03s which is into overspeed territory very quickly it is saturated easily. I'm thinking that with a giant pressure dropping IC and a small trubo that if the turbo has to generate an extra 2psi to compensate for the IC pressure drop, it can only do this by spinning faster but if its already saturated then no more power can be made, just heat. I seriously think the seat sport IC is robbing me of power. Just my two cents but I think that a single pass IC with less pressure drop augmented with water spray or water injection is the way to go on small turbos. As it is I'm going to slowly accumulate parts for either a hybrid K03 or garret which might tale a while so I'll live with it and keep the big FMIC.
High school physics Sam, Boyle's Law, do you remember it?
Keeping in mind that it's not the volume of air but the weight of it that determines an engine’s power output. Using the more recent combinations (temperature added) to Boyle's law, and some rough maths. Assuming that the intake air temp after the small intercooler is, say, 50 degrees and the intake air temp after the large intercooler is 30 degrees. Noting that the temperature used in the formula is absolute, hence add 273.
(273+50)/(273+30) = 1.066 so 6.6% increase.
1 bar = 14.5 psi
14.5 psi + 6.6% = 15.5 psi
So roughly dropping the intake temp 20C will have the same affect as adding 1 psi of boost to the weight of the air into the engine.
Then add the effects of the cooler inlet air on lessening detonation, which means more ignition advance can be used and lower exhaust gas temperature, all of which help power production.
More convincing?
Sorry there's still a little bit more of the rules of thermodynamics left to consider (ooops, more high school physics), the volume of air (in a confined space) is reflected in the pressure, which in our case equals boost. The volume of air changes when it is heated (or cooled) and I don't have a chart handy with 20 to 40 degrees, but I do have one for 22 to 43 degrees. If, say, 2 m3 of air is heated from 22 degrees to 43 degrees, then the volume correction factor is 1.08 and the new volume can be calculated as (2 m3) x 1.08 = 2.16 m3.
Using our small intercooler versus large intercooler temperature difference of 20 degrees that's around 8% less air pressure for the same volume. Hence 14.5 psi (small intercooler) would be 13.3 psi (large intercooler) because the air temperature is lower.
Net result, roughly gaining effectively 1 psi of boost due to weight and loosing roughly 1 psi of boost due to volume.
Any measurable difference greater than say 1 psi between the inlet air pressure into the intercooler and the inlet air pressure out of the intercooler would reflect its internal restriction to airflow. I'd also measure the inlet air temp in and out to give an idea of the efficiency of the intercooler. A really good air to air intercooler is around 75% efficient ie; it will drop the inlet air temp 75& of the difference between the compressor output air temp and the ambient air temp.
Something like, say;
100 degrees out of the compressor
30 degrees ambient
75% efficiency
= 100 - 30 = 70 x 75% = 52.5 degrees temperature drop across the intercooler
100 - 52.5 = 47.5 degrees out of the intercooler.
Hope you had fun with physics today?
Cheers
Gary
Golf Mk7.5 R, Volvo S60 Polestar, Skyline R32GTST
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